Question 1 (5 points)

If f(x) = 4(3x – 5), find ⁻¹ ( ).

Question 1 options:

	a) f−1(x) = x−2012 $f^{–1}\left(x\right)=\frac{x–20}{12}$
	b) f−1(x) = x+54 $f^{–1}\left(x\right)=\frac{x+5}{4}$
	c) f−1(x) = x+2012 $f^{–1}\left(x\right)=\frac{x+20}{12}$
	d) f−1(x) = x+512 $f^{–1}\left(x\right)=\frac{x+5}{12}$

Question 2 (5 points)

What is the slope-intercept form of y + 6 = 2(x + 2)?

Question 2 options:

	a) y = 2x + 6
	b) 2x – y = 6
	c) y = 2x – 6
	d) y = 2x – 2

Question 3 (5 points)

Which correlation coefficient corresponds to the best-fit line that most closely models its set of data?

Question 3 options:

	a) -0.87
	b) -0.15
	c) 0.84
	d) 0.13

Question 4 (5 points)

Find the equation in slope-intercept form that describes a line through (4, –2) with slope –3

Question 4 options:

	a) y = –3x – 2
	b) y = –3x + 4
	c) y = –3x + 10
	d) y = –3x

Question 5 (5 points)

If 5 deli sandwiches cost $29.75, how much will 8 sandwiches cost?

Question 5 options:

	a) $37.75
	b) $29.75
	c) $0.16
	d) $47.60

Question 6 (5 points)

Which variable of time could cause a student’s GPA to increase?

Question 6 options:

	a) working
	b) sleeping
	c) studying
	d) eating

Question 7 (5 points)

Find the equation in slope-intercept form that describes a line through (2, 4) with slope 0

Question 7 options:

	a) y = 4
	b) y = 2
	c) x = 2
	d) x = 4

Question 8 (5 points)

Find the slope-intercept form of an equation of the line perpendicular to the graph of x – 3y = 5 and passing through (0, 6).

Question 8 options:

	a) y = –3x + 6
	b) y = 13x − 2 $y=\frac{1}{3}x–2$
	c) y = 3x – 6
	d) y = 13x + 2 $y=\frac{1}{3}x+2$

Question 9 (5 points)

When are two distinct nonvertical lines parallel?

Question 9 options:

	a) when the slopes are opposite
	b) when the slopes are equal
	c) when the slopes are positive
	d) when the product of the slopes is –1

Question 10 (5 points)

A line of fit might be defined as

Question 10 options:

	a) a line that has a slope greater than 1.
	b) a line that connects all the data points.
	c) a line that might best estimate the data and be used for predicting values.
	d) a vertical line halfway through the data.

Question 11 (5 points)

The table below shows Lia’s bowling score each week she participated in a bowling league.

Use the median-fit line to estimate Lia’s score for week 16.

Question 11 options:

	a) 257
	b) 182
	c) 173
	d) 180

Question 12 (5 points)

Which is the graph of 3x – 4y = 6?

Question 12 options:

	a)
	b)
	c)
	d)

Question 13 (5 points)

What is the standard form of y – 8 = 2(x + 3)?

Question 13 options:

	a) y – 2x = 11
	b) 2x + y = 14
	c) y = 2x + 14
	d) 2x – y = –14

Question 14 (5 points)

Based on the data in the scatter plot, what would you expect the y-value to be for x = ‘20?

Question 14 options:

	a) less than 50
	b) between 80 and 65
	c) between 65 and 50
	d) greater than 80

Question 15 (5 points)

Find the equation in slope-intercept form that describes a line through (4, 2) with slope 12

$\frac{1}{2}$

Question 15 options:

	a) y = 12x $y=\frac{1}{2}x$
	b) y= −12x $y=–\frac{1}{2}x$
	c) y = 12x − 4 $y=\frac{1}{2}x–4$
	d) y = 2x – 10

Question 16 (5 points)

Which is an equation of the line that passes through (–1, –5) and (–3, –7)?

Question 16 options:

	a) y = x – 4
	b) y = –2x + 4
	c) y = 2x + 4
	d) y = –x – 4

Question 17 (5 points)

Which is the point-slope form of an equation for the line that passes through (0, –5) with slope 2?

Question 17 options:

	a) y = 2(x + 5)
	b) y + 5 = 2x
	c) y – 5 = x – 2
	d) y = 2x – 5

Question 18 (5 points)

What is the slope-intercept form of the equation of a line that passes through (1, –6) with a slope of 5?

Question 18 options:

	a) y = 5x + 1
	b) y = 5x – 6
	c) y = 5x – 11
	d) y = 5x + 11

Question 19 (5 points)

Which is an equation of the line with slope –3 and passes through (2, –1)?

Question 19 options:

	a) y = –3(x + 5)
	b) –3x + y = 5
	c) 3x + y = 5
	d) y = 5x – 3

Question 20 (5 points)

If f(x) = 6x + 3, find ⁻¹ ( ).

Question 20 options:

	a) f−1(x) = x−63 $f^{–1}\left(x\right)=\frac{x–6}{3}$
	b) f−1(x) = 6x −3 $f^{–1}\left(x\right)=6x–3$
	c) f−1(x) = x−36 $f^{–1}\left(x\right)=\frac{x–3}{6}$
	d) f−1(x) = −3− 6x $f^{–1}\left(x\right)=–3–6x$

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